Graduate Management Admission Test (GMAT) Practice Test

Disable ads (and more) with a membership for a one time $2.99 payment

Prepare for the GMAT with our interactive quiz. Study with comprehensive multiple-choice questions and detailed explanations. Get ready to ace your exam!

Each practice test/flash card set has 50 randomly selected questions from a bank of over 500. You'll get a new set of questions each time!

Practice this question and more.

In a sequence of consecutive numbers starting from 5, what is the highest number in the sequence n1, n2, n3, ..., n125?

The correct answer is: 129

In this sequence, the numbers are consecutive and start from 5. To find the highest number in the sequence of the first 125 terms (n1, n2, n3, ..., n125), we need to realize that n1 corresponds to the first term, which is 5, and each subsequent term increases by 1. Therefore, the first few numbers in the sequence would be: - n1 = 5 - n2 = 6 - n3 = 7 - ... - n125 = 5 + (125 - 1) Here, we see that to get to the 125th number, we add 124 to the starting point of 5: n125 = 5 + 124 = 129. This calculation shows that the highest number in this sequence of 125 consecutive numbers starting from 5 is indeed 129. Each number is simply the starting point plus the index minus one, which confirms that the answer of 129 is accurate and reflects the pattern of consecutive integers starting from 5.